6(3x^2-3x)-9(2x^2+1)=12

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Solution for 6(3x^2-3x)-9(2x^2+1)=12 equation:


Simplifying
6(3x2 + -3x) + -9(2x2 + 1) = 12

Reorder the terms:
6(-3x + 3x2) + -9(2x2 + 1) = 12
(-3x * 6 + 3x2 * 6) + -9(2x2 + 1) = 12
(-18x + 18x2) + -9(2x2 + 1) = 12

Reorder the terms:
-18x + 18x2 + -9(1 + 2x2) = 12
-18x + 18x2 + (1 * -9 + 2x2 * -9) = 12
-18x + 18x2 + (-9 + -18x2) = 12

Reorder the terms:
-9 + -18x + 18x2 + -18x2 = 12

Combine like terms: 18x2 + -18x2 = 0
-9 + -18x + 0 = 12
-9 + -18x = 12

Solving
-9 + -18x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + -18x = 12 + 9

Combine like terms: -9 + 9 = 0
0 + -18x = 12 + 9
-18x = 12 + 9

Combine like terms: 12 + 9 = 21
-18x = 21

Divide each side by '-18'.
x = -1.166666667

Simplifying
x = -1.166666667

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